Solving Linear Equations Practice Question

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Question 1

Solve the following linear equation:

Algebra equation 2(4n-1)=5n+7

Answer

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Select and check your answer...

A. n = -2
B. n = 3
C. n = -3
D. n = 2

Step by Step Solution

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    Step 1

    To solve the linear equation, we need to remove the brackets first.

    Remove brackets in 2(4n-1)
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    Step 2

    Now, 2 multiply by 4n gives +8n.

    2 multiply by 4n gives +8n
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    Step 3

    Next, 2 multiply by -1 gives -2.

    2 multiply by -1 gives -2
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    Step 4

    Now, the equation becomes:

    Algebra equation +8n-2 = 5n+7
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    Step 5

    With the equation as:

    +8n -2 = 5n +7

    Notice that we can remove 5n by adding -5n to both sides of the equation. Now the equation becomes:

    +8n -5n -2 = 5n -5n +7

    On the Right Hand Side (RHS), 5n and -5n cancel off. We now have:

    Algebra equation +8n -5n -2 = +7
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    Step 6

    Now, with the equation as:

    +8n -5n -2 = +7

    Notice that we can remove -2 by adding +2 to both sides of the equation. Now the equation becomes:

    +8n -5n -2 +2 = +7 +2

    On the Left Hand Side (LHS), -2 and +2 cancel off. We now have:

    Algebra equation +8n -5n = +7 +2
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    Step 7

    Now, adding 8n with -5n gives 3n. Similarly, adding 7 with 2. gives 9.

    The equation becomes 3n = 9.

    Simplify both sides to get 3n = 9
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    Step 8

    Now, we can get n by dividing both sides by 3. The equation becomes:

    3n/3 = 9/3

    Notice that, in the term 3n/3, we can cancel of 3. The equation becomes n = 9/3.

    Divide both sides by 3 to get r = 9/3
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    Step 9

    Now, we divide 9 with 3. We get n = 3. Clearly, the answer is B.

    Answer is n = 3